113201401133001 has 4 divisors (see below), whose sum is σ = 150935201510672. Its totient is φ = 75467600755332.

The previous prime is 113201401132993. The next prime is 113201401133027. The reversal of 113201401133001 is 100331104102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 113201401133001 - 2³ = 113201401132993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113201401133801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18866900188831 + ... + 18866900188836.

It is an arithmetic number, because the mean of its divisors is an integer number (37733800377668).

Almost surely, 2^{113201401133001} is an apocalyptic number.

It is an amenable number.

113201401133001 is a deficient number, since it is larger than the sum of its proper divisors (37733800377671).

113201401133001 is an equidigital number, since it uses as much as digits as its factorization.

113201401133001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37733800377670.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 113201401133001 its reverse (100331104102311), we get a palindrome (213532505235312).

The spelling of 113201401133001 in words is "one hundred thirteen trillion, two hundred one billion, four hundred one million, one hundred thirty-three thousand, one".