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1132031213100 = 2232521937738431
BaseRepresentation
bin10000011110010010010…
…100010111111000101100
311000012222012102222122200
4100132102110113320230
5122021344442304400
62224014205341500
7144533534355324
oct20362224277054
94005865388580
101132031213100
113a7101120537
1216348ab67890
1382999c258c8
143cb0d5b4284
151e6a7aa5b00
hex10792517e2c

1132031213100 has 216 divisors, whose sum is σ = 3571711520832. Its totient is φ = 299886796800.

The previous prime is 1132031213087. The next prime is 1132031213153. The reversal of 1132031213100 is 13121302311.

1132031213100 is a `hidden beast` number, since 1 + 1 + 320 + 31 + 2 + 1 + 310 + 0 = 666.

It is a super-2 number, since 2×11320312131002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 134265885 + ... + 134274315.

Almost surely, 21132031213100 is an apocalyptic number.

1132031213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1132031213100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1785855760416).

1132031213100 is an abundant number, since it is smaller than the sum of its proper divisors (2439680307732).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1132031213100 is a wasteful number, since it uses less digits than its factorization.

1132031213100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9417 (or 9407 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1132031213100 its reverse (13121302311), we get a palindrome (1145152515411).

The spelling of 1132031213100 in words is "one trillion, one hundred thirty-two billion, thirty-one million, two hundred thirteen thousand, one hundred".