Base | Representation |
---|---|
bin | 110100101101101110… |
… | …0010100101100001011 |
3 | 101211012022222112102201 |
4 | 1221123130110230023 |
5 | 3323320021114011 |
6 | 124001015341031 |
7 | 11115166116544 |
oct | 1513334245413 |
9 | 354168875381 |
10 | 113203301131 |
11 | 44011348718 |
12 | 19b33681777 |
13 | a8a105316b |
14 | 569c7cb4cb |
15 | 2e28448cc1 |
hex | 1a5b714b0b |
113203301131 has 2 divisors, whose sum is σ = 113203301132. Its totient is φ = 113203301130.
The previous prime is 113203301093. The next prime is 113203301149. The reversal of 113203301131 is 131103302311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113203301131 - 221 = 113201203979 is a prime.
It is a super-2 number, since 2×1132033011312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113203301099 and 113203301108.
It is not a weakly prime, because it can be changed into another prime (113203371131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56601650565 + 56601650566.
It is an arithmetic number, because the mean of its divisors is an integer number (56601650566).
Almost surely, 2113203301131 is an apocalyptic number.
113203301131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113203301131 is an equidigital number, since it uses as much as digits as its factorization.
113203301131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 113203301131 its reverse (131103302311), we get a palindrome (244306603442).
The spelling of 113203301131 in words is "one hundred thirteen billion, two hundred three million, three hundred one thousand, one hundred thirty-one".
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