Base | Representation |
---|---|
bin | 11001101111010101000110… |
… | …001110111100000001010011 |
3 | 112211211011100201010000022211 |
4 | 121233111012032330001103 |
5 | 104314212014110413101 |
6 | 1040433010313412551 |
7 | 32562456341566564 |
oct | 3157250616740123 |
9 | 484734321100284 |
10 | 113203631341651 |
11 | 33085432752874 |
12 | 1084375710a157 |
13 | 4b220975551a6 |
14 | 1dd512930616b |
15 | d14a460cdc51 |
hex | 66f5463bc053 |
113203631341651 has 4 divisors (see below), whose sum is σ = 113898132147592. Its totient is φ = 112509130535712.
The previous prime is 113203631341627. The next prime is 113203631341693. The reversal of 113203631341651 is 156143136302311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113203631341651 - 233 = 113195041407059 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113203631348651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347250402726 + ... + 347250403051.
It is an arithmetic number, because the mean of its divisors is an integer number (28474533036898).
Almost surely, 2113203631341651 is an apocalyptic number.
113203631341651 is a deficient number, since it is larger than the sum of its proper divisors (694500805941).
113203631341651 is an equidigital number, since it uses as much as digits as its factorization.
113203631341651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 694500805940.
The product of its (nonzero) digits is 116640, while the sum is 40.
Adding to 113203631341651 its reverse (156143136302311), we get a palindrome (269346767643962).
The spelling of 113203631341651 in words is "one hundred thirteen trillion, two hundred three billion, six hundred thirty-one million, three hundred forty-one thousand, six hundred fifty-one".
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