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113205107153 is a prime number
BaseRepresentation
bin110100101101110001…
…1001101100111010001
3101211012110101021211102
41221123203031213101
53323321001412103
6124001122154145
711115220351115
oct1513343154721
9354173337742
10113205107153
11440123715a6
1219b341b2955
13a8a1536208
14569cb3b745
152e286a3e88
hex1a5b8cd9d1

113205107153 has 2 divisors, whose sum is σ = 113205107154. Its totient is φ = 113205107152.

The previous prime is 113205107149. The next prime is 113205107177. The reversal of 113205107153 is 351701502311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105239901649 + 7965205504 = 324407^2 + 89248^2 .

It is a cyclic number.

It is not a de Polignac number, because 113205107153 - 22 = 113205107149 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113205107753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56602553576 + 56602553577.

It is an arithmetic number, because the mean of its divisors is an integer number (56602553577).

Almost surely, 2113205107153 is an apocalyptic number.

It is an amenable number.

113205107153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113205107153 is an equidigital number, since it uses as much as digits as its factorization.

113205107153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3150, while the sum is 29.

Adding to 113205107153 its reverse (351701502311), we get a palindrome (464906609464).

The spelling of 113205107153 in words is "one hundred thirteen billion, two hundred five million, one hundred seven thousand, one hundred fifty-three".