Base | Representation |
---|---|
bin | 1010010010111110000000… |
… | …1011101111101000010001 |
3 | 1111002021110221210020102221 |
4 | 2210233200023233220101 |
5 | 2440440402000000032 |
6 | 40024443503341041 |
7 | 2245625635153561 |
oct | 244574013575021 |
9 | 44067427706387 |
10 | 11321000000017 |
11 | 36752333a9024 |
12 | 132a103bb1781 |
13 | 641747b67776 |
14 | 2b1d2170ada1 |
15 | 1497427b5597 |
hex | a4be02efa11 |
11321000000017 has 2 divisors, whose sum is σ = 11321000000018. Its totient is φ = 11321000000016.
The previous prime is 11321000000003. The next prime is 11321000000021. The reversal of 11321000000017 is 71000000012311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7662842657856 + 3658157342161 = 2768184^2 + 1912631^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11321000000017 is a prime.
It is not a weakly prime, because it can be changed into another prime (11321000000087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660500000008 + 5660500000009.
It is an arithmetic number, because the mean of its divisors is an integer number (5660500000009).
Almost surely, 211321000000017 is an apocalyptic number.
It is an amenable number.
11321000000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321000000017 is an equidigital number, since it uses as much as digits as its factorization.
11321000000017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42, while the sum is 16.
Adding to 11321000000017 its reverse (71000000012311), we get a palindrome (82321000012328).
The spelling of 11321000000017 in words is "eleven trillion, three hundred twenty-one billion, seventeen", and thus it is an aban number.
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