Base | Representation |
---|---|
bin | 11001101111011101111011… |
… | …001101001001101000101011 |
3 | 112211212001211021212202101111 |
4 | 121233131323031021220223 |
5 | 104314340422130001141 |
6 | 1040441215034131151 |
7 | 32563243256060536 |
oct | 3157357315115053 |
9 | 484761737782344 |
10 | 113213110000171 |
11 | 33089457154255 |
12 | 10845561580ab7 |
13 | 4b22c4822767c |
14 | 1dd5788119a1d |
15 | d14ded30a381 |
hex | 66f77b349a2b |
113213110000171 has 2 divisors, whose sum is σ = 113213110000172. Its totient is φ = 113213110000170.
The previous prime is 113213110000121. The next prime is 113213110000201. The reversal of 113213110000171 is 171000011312311.
It is a strong prime.
It is an emirp because it is prime and its reverse (171000011312311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113213110000171 - 211 = 113213109998123 is a prime.
It is not a weakly prime, because it can be changed into another prime (113213110000121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56606555000085 + 56606555000086.
It is an arithmetic number, because the mean of its divisors is an integer number (56606555000086).
Almost surely, 2113213110000171 is an apocalyptic number.
113213110000171 is a deficient number, since it is larger than the sum of its proper divisors (1).
113213110000171 is an equidigital number, since it uses as much as digits as its factorization.
113213110000171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 22.
Adding to 113213110000171 its reverse (171000011312311), we get a palindrome (284213121312482).
The spelling of 113213110000171 in words is "one hundred thirteen trillion, two hundred thirteen billion, one hundred ten million, one hundred seventy-one", and thus it is an aban number.
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