113214022081 has 2 divisors, whose sum is σ = 113214022082. Its totient is φ = 113214022080.

The previous prime is 113214022067. The next prime is 113214022093. The reversal of 113214022081 is 180220412311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60791340481 + 52422681600 = 246559^2 + 228960^2 .

It is a cyclic number.

It is not a de Polignac number, because 113214022081 - 2¹¹ = 113214020033 is a prime.

It is a super-3 number, since 3×113214022081³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (113214022381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56607011040 + 56607011041.

It is an arithmetic number, because the mean of its divisors is an integer number (56607011041).

Almost surely, 2^113214022081 is an apocalyptic number.

It is an amenable number.

113214022081 is a deficient number, since it is larger than the sum of its proper divisors (1).

113214022081 is an equidigital number, since it uses as much as digits as its factorization.

113214022081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 113214022081 its reverse (180220412311), we get a palindrome (293434434392).

The spelling of 113214022081 in words is "one hundred thirteen billion, two hundred fourteen million, twenty-two thousand, eighty-one".