11322011040433 has 4 divisors (see below), whose sum is σ = 11329835513920. Its totient is φ = 11314186566948.

The previous prime is 11322011040421. The next prime is 11322011040437. The reversal of 11322011040433 is 33404011022311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11322011040433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11322011040398 and 11322011040407.

It is not an unprimeable number, because it can be changed into a prime (11322011040437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3912234573 + ... + 3912237466.

It is an arithmetic number, because the mean of its divisors is an integer number (2832458878480).

Almost surely, 2^{11322011040433} is an apocalyptic number.

It is an amenable number.

11322011040433 is a deficient number, since it is larger than the sum of its proper divisors (7824473487).

11322011040433 is an equidigital number, since it uses as much as digits as its factorization.

11322011040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7824473486.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11322011040433 its reverse (33404011022311), we get a palindrome (44726022062744).

The spelling of 11322011040433 in words is "eleven trillion, three hundred twenty-two billion, eleven million, forty thousand, four hundred thirty-three".