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113220201233 = 156717224823
BaseRepresentation
bin110100101110001110…
…0110010101100010001
3101211020111210011000102
41221130130302230101
53323333332414413
6124002421502145
711115462555146
oct1513434625421
9354214704012
10113220201233
114401a940a47
1219b39271955
13a8a46bc619
1456a0b4a3cd
152e29b86458
hex1a5c732b11

113220201233 has 4 divisors (see below), whose sum is σ = 113227441728. Its totient is φ = 113212960740.

The previous prime is 113220201209. The next prime is 113220201247. The reversal of 113220201233 is 332102022311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113220201233 - 230 = 112146459409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113220201533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3596741 + ... + 3628082.

It is an arithmetic number, because the mean of its divisors is an integer number (28306860432).

Almost surely, 2113220201233 is an apocalyptic number.

It is an amenable number.

113220201233 is a deficient number, since it is larger than the sum of its proper divisors (7240495).

113220201233 is an equidigital number, since it uses as much as digits as its factorization.

113220201233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7240494.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 113220201233 its reverse (332102022311), we get a palindrome (445322223544).

The spelling of 113220201233 in words is "one hundred thirteen billion, two hundred twenty million, two hundred one thousand, two hundred thirty-three".

Divisors: 1 15671 7224823 113220201233