Base | Representation |
---|---|
bin | 1010010011000001110100… |
… | …0011000000110110010011 |
3 | 1111002101010010012120200102 |
4 | 2210300131003000312103 |
5 | 2440444444401341202 |
6 | 40025133101443015 |
7 | 2245663144434122 |
oct | 244603503006623 |
9 | 44071103176612 |
10 | 11322021121427 |
11 | 3675707838715 |
12 | 132a349b7046b |
13 | 64187b58b613 |
14 | 2b1dbb195ab9 |
15 | 1497a2269d02 |
hex | a4c1d0c0d93 |
11322021121427 has 2 divisors, whose sum is σ = 11322021121428. Its totient is φ = 11322021121426.
The previous prime is 11322021121423. The next prime is 11322021121513. The reversal of 11322021121427 is 72412112022311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11322021121427 - 22 = 11322021121423 is a prime.
It is a super-3 number, since 3×113220211214273 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11322021121427.
It is not a weakly prime, because it can be changed into another prime (11322021121423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661010560713 + 5661010560714.
It is an arithmetic number, because the mean of its divisors is an integer number (5661010560714).
Almost surely, 211322021121427 is an apocalyptic number.
11322021121427 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322021121427 is an equidigital number, since it uses as much as digits as its factorization.
11322021121427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 11322021121427 its reverse (72412112022311), we get a palindrome (83734133143738).
The spelling of 11322021121427 in words is "eleven trillion, three hundred twenty-two billion, twenty-one million, one hundred twenty-one thousand, four hundred twenty-seven".
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