Base | Representation |
---|---|
bin | 10000011110011100100… |
… | …000010101001110110001 |
3 | 11000020102010000222000001 |
4 | 100132130200111032301 |
5 | 122022222220320423 |
6 | 2224043152430001 |
7 | 144541011142441 |
oct | 20363440251661 |
9 | 4006363028001 |
10 | 1132202120113 |
11 | 3a71896424a9 |
12 | 163518248301 |
13 | 829c6464a0c |
14 | 3cb28182121 |
15 | 1e6b7ab4cad |
hex | 1079c8153b1 |
1132202120113 has 2 divisors, whose sum is σ = 1132202120114. Its totient is φ = 1132202120112.
The previous prime is 1132202120107. The next prime is 1132202120129. The reversal of 1132202120113 is 3110212022311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 903151817649 + 229050302464 = 950343^2 + 478592^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132202120113 - 217 = 1132201989041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132202120173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566101060056 + 566101060057.
It is an arithmetic number, because the mean of its divisors is an integer number (566101060057).
Almost surely, 21132202120113 is an apocalyptic number.
It is an amenable number.
1132202120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132202120113 is an equidigital number, since it uses as much as digits as its factorization.
1132202120113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1132202120113 its reverse (3110212022311), we get a palindrome (4242414142424).
The spelling of 1132202120113 in words is "one trillion, one hundred thirty-two billion, two hundred two million, one hundred twenty thousand, one hundred thirteen".
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