11322044140331 has 4 divisors (see below), whose sum is σ = 11322055229472. Its totient is φ = 11322033051192.

The previous prime is 11322044140259. The next prime is 11322044140409. The reversal of 11322044140331 is 13304144022311.

11322044140331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11322044140331 is a prime.

It is a super-2 number, since 2×11322044140331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11322044140294 and 11322044140303.

It is not an unprimeable number, because it can be changed into a prime (11322044140531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3837971 + ... + 6113436.

It is an arithmetic number, because the mean of its divisors is an integer number (2830513807368).

Almost surely, 2^{11322044140331} is an apocalyptic number.

11322044140331 is a deficient number, since it is larger than the sum of its proper divisors (11089141).

11322044140331 is an equidigital number, since it uses as much as digits as its factorization.

11322044140331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11089140.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11322044140331 its reverse (13304144022311), we get a palindrome (24626188162642).

The spelling of 11322044140331 in words is "eleven trillion, three hundred twenty-two billion, forty-four million, one hundred forty thousand, three hundred thirty-one".