Base | Representation |
---|---|
bin | 1010010011000010100001… |
… | …1111110010010000100001 |
3 | 1111002101121111122212002011 |
4 | 2210300220133302100201 |
5 | 2441000343040310332 |
6 | 40025204122552521 |
7 | 2246000666253364 |
oct | 244605037622041 |
9 | 44071544585064 |
10 | 11322213213217 |
11 | 36757a620a065 |
12 | 132a3a2368741 |
13 | 6418ac3071ba |
14 | 2b1dd88ba0db |
15 | 1497b4060e47 |
hex | a4c287f2421 |
11322213213217 has 2 divisors, whose sum is σ = 11322213213218. Its totient is φ = 11322213213216.
The previous prime is 11322213213193. The next prime is 11322213213221. The reversal of 11322213213217 is 71231231222311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9799911291361 + 1522301921856 = 3130481^2 + 1233816^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11322213213217 is a prime.
It is not a weakly prime, because it can be changed into another prime (11322213213917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661106606608 + 5661106606609.
It is an arithmetic number, because the mean of its divisors is an integer number (5661106606609).
Almost surely, 211322213213217 is an apocalyptic number.
It is an amenable number.
11322213213217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322213213217 is an equidigital number, since it uses as much as digits as its factorization.
11322213213217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6048, while the sum is 31.
Adding to 11322213213217 its reverse (71231231222311), we get a palindrome (82553444435528).
The spelling of 11322213213217 in words is "eleven trillion, three hundred twenty-two billion, two hundred thirteen million, two hundred thirteen thousand, two hundred seventeen".
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