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1132221436153 is a prime number
BaseRepresentation
bin10000011110011101101…
…010000001000011111001
311000020110110101022121221
4100132131222001003321
5122022242141424103
62224045122432041
7144541334262433
oct20363552010371
94006413338557
101132221436153
113a7199535975
12163522802621
13829ca468a22
143cb2a96d653
151e6b962d1bd
hex1079da810f9

1132221436153 has 2 divisors, whose sum is σ = 1132221436154. Its totient is φ = 1132221436152.

The previous prime is 1132221436109. The next prime is 1132221436169. The reversal of 1132221436153 is 3516341222311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 888394847209 + 243826588944 = 942547^2 + 493788^2 .

It is an emirp because it is prime and its reverse (3516341222311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1132221436153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1132221436253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566110718076 + 566110718077.

It is an arithmetic number, because the mean of its divisors is an integer number (566110718077).

Almost surely, 21132221436153 is an apocalyptic number.

It is an amenable number.

1132221436153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132221436153 is an equidigital number, since it uses as much as digits as its factorization.

1132221436153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25920, while the sum is 34.

Adding to 1132221436153 its reverse (3516341222311), we get a palindrome (4648562658464).

The spelling of 1132221436153 in words is "one trillion, one hundred thirty-two billion, two hundred twenty-one million, four hundred thirty-six thousand, one hundred fifty-three".