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11323112132001 = 33774370710667
BaseRepresentation
bin1010010011000101111000…
…0100111000110110100001
31111002110221011010122211110
42210301132010320312201
52441004213201211001
640025433233533533
72246032163040015
oct244613604706641
944073834118743
1011323112132001
11367611767304a
12132a5b34142a9
136419c36126c7
142b2082034545
15149817e273d6
hexa4c5e138da1

11323112132001 has 4 divisors (see below), whose sum is σ = 15097482842672. Its totient is φ = 7548741421332.

The previous prime is 11323112131999. The next prime is 11323112132023. The reversal of 11323112132001 is 10023121132311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11323112132001 - 21 = 11323112131999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11323112332001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1887185355331 + ... + 1887185355336.

It is an arithmetic number, because the mean of its divisors is an integer number (3774370710668).

Almost surely, 211323112132001 is an apocalyptic number.

It is an amenable number.

11323112132001 is a deficient number, since it is larger than the sum of its proper divisors (3774370710671).

11323112132001 is an equidigital number, since it uses as much as digits as its factorization.

11323112132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3774370710670.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 11323112132001 its reverse (10023121132311), we get a palindrome (21346233264312).

The spelling of 11323112132001 in words is "eleven trillion, three hundred twenty-three billion, one hundred twelve million, one hundred thirty-two thousand, one".

Divisors: 1 3 3774370710667 11323112132001