Base | Representation |
---|---|
bin | 1010010011000101111100… |
… | …1001000011001010000001 |
3 | 1111002110222101202110010020 |
4 | 2210301133021003022001 |
5 | 2441004232240000001 |
6 | 40025435112524053 |
7 | 2246032500646221 |
oct | 244613711031201 |
9 | 44073871673106 |
10 | 11323130000001 |
11 | 3676126767596 |
12 | 132a5b93b0629 |
13 | 6419c722a5a1 |
14 | 2b2084566081 |
15 | 1498197a6736 |
hex | a4c5f243281 |
11323130000001 has 8 divisors (see below), whose sum is σ = 15102041827680. Its totient is φ = 7546485752832.
The previous prime is 11323129999991. The next prime is 11323130000059. The reversal of 11323130000001 is 10000003132311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11323130000001 - 25 = 11323129999969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11323130004001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 566883475 + ... + 566903448.
It is an arithmetic number, because the mean of its divisors is an integer number (1887755228460).
Almost surely, 211323130000001 is an apocalyptic number.
It is an amenable number.
11323130000001 is a deficient number, since it is larger than the sum of its proper divisors (3778911827679).
11323130000001 is a wasteful number, since it uses less digits than its factorization.
11323130000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1133790255.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11323130000001 its reverse (10000003132311), we get a palindrome (21323133132312).
The spelling of 11323130000001 in words is "eleven trillion, three hundred twenty-three billion, one hundred thirty million, one", and thus it is an aban number.
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