Base | Representation |
---|---|
bin | 1010010011000101111100… |
… | …1010001111001001001011 |
3 | 1111002110222102100021001201 |
4 | 2210301133022033021023 |
5 | 2441004232324424433 |
6 | 40025435123325031 |
7 | 2246032503413512 |
oct | 244613712171113 |
9 | 44073872307051 |
10 | 11323130311243 |
11 | 367612695a413 |
12 | 132a5b9520777 |
13 | 6419c730915a |
14 | 2b2084607679 |
15 | 149819818a7d |
hex | a4c5f28f24b |
11323130311243 has 2 divisors, whose sum is σ = 11323130311244. Its totient is φ = 11323130311242.
The previous prime is 11323130311231. The next prime is 11323130311267. The reversal of 11323130311243 is 34211303132311.
11323130311243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11323130311243 - 241 = 9124107055691 is a prime.
It is not a weakly prime, because it can be changed into another prime (11323130318243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661565155621 + 5661565155622.
It is an arithmetic number, because the mean of its divisors is an integer number (5661565155622).
Almost surely, 211323130311243 is an apocalyptic number.
11323130311243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323130311243 is an equidigital number, since it uses as much as digits as its factorization.
11323130311243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 11323130311243 its reverse (34211303132311), we get a palindrome (45534433443554).
The spelling of 11323130311243 in words is "eleven trillion, three hundred twenty-three billion, one hundred thirty million, three hundred eleven thousand, two hundred forty-three".
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