Base | Representation |
---|---|
bin | 110100101110100011… |
… | …1100001000111110001 |
3 | 101211021021212011211112 |
4 | 1221131013201013301 |
5 | 3323344214321312 |
6 | 124003501523105 |
7 | 11115660013646 |
oct | 1513507410761 |
9 | 354237764745 |
10 | 113231401457 |
11 | 440261a0929 |
12 | 19b40b73495 |
13 | a8a6b11585 |
14 | 56a2423dcd |
15 | 2e2ab49d22 |
hex | 1a5d1e11f1 |
113231401457 has 2 divisors, whose sum is σ = 113231401458. Its totient is φ = 113231401456.
The previous prime is 113231401421. The next prime is 113231401487. The reversal of 113231401457 is 754104132311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109523931136 + 3707470321 = 330944^2 + 60889^2 .
It is an emirp because it is prime and its reverse (754104132311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113231401457 - 210 = 113231400433 is a prime.
It is not a weakly prime, because it can be changed into another prime (113231401487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615700728 + 56615700729.
It is an arithmetic number, because the mean of its divisors is an integer number (56615700729).
Almost surely, 2113231401457 is an apocalyptic number.
It is an amenable number.
113231401457 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231401457 is an equidigital number, since it uses as much as digits as its factorization.
113231401457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 113231401457 its reverse (754104132311), we get a palindrome (867335533768).
The spelling of 113231401457 in words is "one hundred thirteen billion, two hundred thirty-one million, four hundred one thousand, four hundred fifty-seven".
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