Base | Representation |
---|---|
bin | 1010010011000110010000… |
… | …0010001111001001101001 |
3 | 1111002111012010020120102101 |
4 | 2210301210002033021221 |
5 | 2441004414244201301 |
6 | 40025451204333401 |
7 | 2246034515540341 |
oct | 244614402171151 |
9 | 44074163216371 |
10 | 11323212100201 |
11 | 36761690426a1 |
12 | 132a6209a4261 |
13 | 641a0b2448a1 |
14 | 2b2091417d21 |
15 | 149821ac2701 |
hex | a4c6408f269 |
11323212100201 has 2 divisors, whose sum is σ = 11323212100202. Its totient is φ = 11323212100200.
The previous prime is 11323212100141. The next prime is 11323212100219. The reversal of 11323212100201 is 10200121232311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7687859744601 + 3635352355600 = 2772699^2 + 1906660^2 .
It is a cyclic number.
It is not a de Polignac number, because 11323212100201 - 213 = 11323212092009 is a prime.
It is a super-2 number, since 2×113232121002012 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11323212100241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661606050100 + 5661606050101.
It is an arithmetic number, because the mean of its divisors is an integer number (5661606050101).
Almost surely, 211323212100201 is an apocalyptic number.
It is an amenable number.
11323212100201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323212100201 is an equidigital number, since it uses as much as digits as its factorization.
11323212100201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11323212100201 its reverse (10200121232311), we get a palindrome (21523333332512).
The spelling of 11323212100201 in words is "eleven trillion, three hundred twenty-three billion, two hundred twelve million, one hundred thousand, two hundred one".
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