Base | Representation |
---|---|
bin | 1010010011000110010000… |
… | …0010101101001010010011 |
3 | 1111002111012010110211001001 |
4 | 2210301210002231022103 |
5 | 2441004414312114443 |
6 | 40025451211122431 |
7 | 2246034516561613 |
oct | 244614402551223 |
9 | 44074163424031 |
10 | 11323212223123 |
11 | 3676169116a89 |
12 | 132a620a43417 |
13 | 641a0b288818 |
14 | 2b209144aa43 |
15 | 149821ae8d4d |
hex | a4c640ad293 |
11323212223123 has 2 divisors, whose sum is σ = 11323212223124. Its totient is φ = 11323212223122.
The previous prime is 11323212223109. The next prime is 11323212223153. The reversal of 11323212223123 is 32132221232311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11323212223123 - 225 = 11323178668691 is a prime.
It is a super-2 number, since 2×113232122231232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11323212223091 and 11323212223100.
It is not a weakly prime, because it can be changed into another prime (11323212223153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661606111561 + 5661606111562.
It is an arithmetic number, because the mean of its divisors is an integer number (5661606111562).
Almost surely, 211323212223123 is an apocalyptic number.
11323212223123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323212223123 is an equidigital number, since it uses as much as digits as its factorization.
11323212223123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 11323212223123 its reverse (32132221232311), we get a palindrome (43455433455434).
The spelling of 11323212223123 in words is "eleven trillion, three hundred twenty-three billion, two hundred twelve million, two hundred twenty-three thousand, one hundred twenty-three".
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