Base | Representation |
---|---|
bin | 110100101110100101… |
… | …0010101111011010001 |
3 | 101211021100020210201021 |
4 | 1221131022111323101 |
5 | 3323344412021113 |
6 | 124003525435441 |
7 | 11115666220033 |
oct | 1513512257321 |
9 | 354240223637 |
10 | 113232142033 |
11 | 4402665727a |
12 | 19b4126bb81 |
13 | a8a701069a |
14 | 56a2577c53 |
15 | 2e2ac4448d |
hex | 1a5d295ed1 |
113232142033 has 8 divisors (see below), whose sum is σ = 117369798656. Its totient is φ = 109124798400.
The previous prime is 113232141959. The next prime is 113232142117. The reversal of 113232142033 is 330241232311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113232142033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113232141989 and 113232142007.
It is not an unprimeable number, because it can be changed into a prime (113232142433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7570641 + ... + 7585582.
It is an arithmetic number, because the mean of its divisors is an integer number (14671224832).
Almost surely, 2113232142033 is an apocalyptic number.
It is an amenable number.
113232142033 is a deficient number, since it is larger than the sum of its proper divisors (4137656623).
113232142033 is a wasteful number, since it uses less digits than its factorization.
113232142033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15156495.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 113232142033 its reverse (330241232311), we get a palindrome (443473374344).
The spelling of 113232142033 in words is "one hundred thirteen billion, two hundred thirty-two million, one hundred forty-two thousand, thirty-three".
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