Base | Representation |
---|---|
bin | 10101000101110101… |
… | …01111111001010001 |
3 | 1002020010200101210121 |
4 | 22202322233321101 |
5 | 141142222302423 |
6 | 5111332230241 |
7 | 550412662336 |
oct | 124272577121 |
9 | 32203611717 |
10 | 11323244113 |
11 | 4890748995 |
12 | 224016b381 |
13 | 10b5ba335c |
14 | 795bb498d |
15 | 46414045d |
hex | 2a2eafe51 |
11323244113 has 4 divisors (see below), whose sum is σ = 11386502640. Its totient is φ = 11259985588.
The previous prime is 11323244099. The next prime is 11323244143. The reversal of 11323244113 is 31144232311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11323244113 - 221 = 11321146961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11323244143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31628995 + ... + 31629352.
It is an arithmetic number, because the mean of its divisors is an integer number (2846625660).
Almost surely, 211323244113 is an apocalyptic number.
It is an amenable number.
11323244113 is a deficient number, since it is larger than the sum of its proper divisors (63258527).
11323244113 is an equidigital number, since it uses as much as digits as its factorization.
11323244113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63258526.
The product of its digits is 1728, while the sum is 25.
Adding to 11323244113 its reverse (31144232311), we get a palindrome (42467476424).
The spelling of 11323244113 in words is "eleven billion, three hundred twenty-three million, two hundred forty-four thousand, one hundred thirteen".
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