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113233001211313 is a prime number
BaseRepresentation
bin11001101111110000011100…
…110100000110010110110001
3112211220222011112200222101021
4121233300130310012112301
5104320202141302230223
61040454304515535441
732564546220426004
oct3157603464062661
9484828145628337
10113233001211313
1133096934229625
1210849392bba581
134b24a982022a9
141dd6713ba353b
15d156b473765d
hex66fc1cd065b1

113233001211313 has 2 divisors, whose sum is σ = 113233001211314. Its totient is φ = 113233001211312.

The previous prime is 113233001211287. The next prime is 113233001211371. The reversal of 113233001211313 is 313112100332311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112136599554849 + 1096401656464 = 10589457^2 + 1047092^2 .

It is a cyclic number.

It is not a de Polignac number, because 113233001211313 - 245 = 78048629122481 is a prime.

It is a super-2 number, since 2×1132330012113132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113233001211613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616500605656 + 56616500605657.

It is an arithmetic number, because the mean of its divisors is an integer number (56616500605657).

Almost surely, 2113233001211313 is an apocalyptic number.

It is an amenable number.

113233001211313 is a deficient number, since it is larger than the sum of its proper divisors (1).

113233001211313 is an equidigital number, since it uses as much as digits as its factorization.

113233001211313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 113233001211313 its reverse (313112100332311), we get a palindrome (426345101543624).

The spelling of 113233001211313 in words is "one hundred thirteen trillion, two hundred thirty-three billion, one million, two hundred eleven thousand, three hundred thirteen".