Base | Representation |
---|---|
bin | 1010010011000110101001… |
… | …1101110101111000000001 |
3 | 1111002111110122021110010021 |
4 | 2210301222131311320001 |
5 | 2441010124410000001 |
6 | 40025510021133441 |
7 | 2246040265634122 |
oct | 244615235657001 |
9 | 44074418243107 |
10 | 11323320000001 |
11 | 3676213a3a389 |
12 | 132a650b5a281 |
13 | 641a276c3019 |
14 | 2b20a18a4049 |
15 | 14982b2d7ba1 |
hex | a4c6a775e01 |
11323320000001 has 2 divisors, whose sum is σ = 11323320000002. Its totient is φ = 11323320000000.
The previous prime is 11323319999977. The next prime is 11323320000029. The reversal of 11323320000001 is 10000002332311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6939325747600 + 4383994252401 = 2634260^2 + 2093799^2 .
It is a cyclic number.
It is not a de Polignac number, because 11323320000001 - 217 = 11323319868929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11323320000001.
It is not a weakly prime, because it can be changed into another prime (11323320000901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661660000000 + 5661660000001.
It is an arithmetic number, because the mean of its divisors is an integer number (5661660000001).
Almost surely, 211323320000001 is an apocalyptic number.
It is an amenable number.
11323320000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323320000001 is an equidigital number, since it uses as much as digits as its factorization.
11323320000001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 11323320000001 its reverse (10000002332311), we get a palindrome (21323322332312).
The spelling of 11323320000001 in words is "eleven trillion, three hundred twenty-three billion, three hundred twenty million, one", and thus it is an aban number.
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