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113240021113 is a prime number
BaseRepresentation
bin110100101110110100…
…0011001100001111001
3101211021220002002210001
41221131220121201321
53323403421133423
6124004410353001
711116123204102
oct1513550314171
9354256062701
10113240021113
1144030048a0a
1219b43a2b761
13a8a883ba6b
1456a36293a9
152e2b79dcad
hex1a5da19879

113240021113 has 2 divisors, whose sum is σ = 113240021114. Its totient is φ = 113240021112.

The previous prime is 113240021057. The next prime is 113240021137. The reversal of 113240021113 is 311120042311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100636141824 + 12603879289 = 317232^2 + 112267^2 .

It is a cyclic number.

It is not a de Polignac number, because 113240021113 - 217 = 113239890041 is a prime.

It is a super-3 number, since 3×1132400211133 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (113240021183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620010556 + 56620010557.

It is an arithmetic number, because the mean of its divisors is an integer number (56620010557).

Almost surely, 2113240021113 is an apocalyptic number.

It is an amenable number.

113240021113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113240021113 is an equidigital number, since it uses as much as digits as its factorization.

113240021113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 113240021113 its reverse (311120042311), we get a palindrome (424360063424).

The spelling of 113240021113 in words is "one hundred thirteen billion, two hundred forty million, twenty-one thousand, one hundred thirteen".