Base | Representation |
---|---|
bin | 10101000101111011… |
… | …01011001100100110 |
3 | 1002020012010101012000 |
4 | 22202331223030212 |
5 | 141142421330202 |
6 | 5111400510130 |
7 | 550422336132 |
oct | 124275531446 |
9 | 32205111160 |
10 | 11324011302 |
11 | 489112232a |
12 | 224047b346 |
13 | 10b60b1606 |
14 | 795d343c2 |
15 | 46424291c |
hex | 2a2f6b326 |
11324011302 has 32 divisors (see below), whose sum is σ = 25169356800. Its totient is φ = 3773937384.
The previous prime is 11324011301. The next prime is 11324011319. The reversal of 11324011302 is 20311042311.
11324011302 is a `hidden beast` number, since 1 + 132 + 401 + 130 + 2 = 666.
It is a super-3 number, since 3×113240113023 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324011301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 309199 + ... + 343877.
It is an arithmetic number, because the mean of its divisors is an integer number (786542400).
Almost surely, 211324011302 is an apocalyptic number.
11324011302 is an abundant number, since it is smaller than the sum of its proper divisors (13845345498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11324011302 is a wasteful number, since it uses less digits than its factorization.
11324011302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40737 (or 40731 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11324011302 its reverse (20311042311), we get a palindrome (31635053613).
The spelling of 11324011302 in words is "eleven billion, three hundred twenty-four million, eleven thousand, three hundred two".
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