Base | Representation |
---|---|
bin | 10101000101111011… |
… | …10010011101001001 |
3 | 1002020012011212222011 |
4 | 22202331302131021 |
5 | 141142423303113 |
6 | 5111401255521 |
7 | 550422521614 |
oct | 124275623511 |
9 | 32205155864 |
10 | 11324041033 |
11 | 48911426a8 |
12 | 22404945a1 |
13 | 10b60c1cc6 |
14 | 795d4117b |
15 | 46424b63d |
hex | 2a2f72749 |
11324041033 has 2 divisors, whose sum is σ = 11324041034. Its totient is φ = 11324041032.
The previous prime is 11324040997. The next prime is 11324041039. The reversal of 11324041033 is 33014042311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7914415369 + 3409625664 = 88963^2 + 58392^2 .
It is an emirp because it is prime and its reverse (33014042311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11324041033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11324040995 and 11324041013.
It is not a weakly prime, because it can be changed into another prime (11324041039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662020516 + 5662020517.
It is an arithmetic number, because the mean of its divisors is an integer number (5662020517).
Almost surely, 211324041033 is an apocalyptic number.
It is an amenable number.
11324041033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11324041033 is an equidigital number, since it uses as much as digits as its factorization.
11324041033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 11324041033 its reverse (33014042311), we get a palindrome (44338083344).
The spelling of 11324041033 in words is "eleven billion, three hundred twenty-four million, forty-one thousand, thirty-three".
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