Base | Representation |
---|---|
bin | 110100101110110110… |
… | …0010010100101001011 |
3 | 101211021221222221010001 |
4 | 1221131230102211023 |
5 | 3323404201304402 |
6 | 124004444303431 |
7 | 11116134653146 |
oct | 1513554224513 |
9 | 354257887101 |
10 | 113241041227 |
11 | 44030685386 |
12 | 19b44241b77 |
13 | a8a8b08192 |
14 | 56a381305d |
15 | 2e2b901187 |
hex | 1a5db1294b |
113241041227 has 2 divisors, whose sum is σ = 113241041228. Its totient is φ = 113241041226.
The previous prime is 113241041209. The next prime is 113241041261. The reversal of 113241041227 is 722140142311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113241041227 - 227 = 113106823499 is a prime.
It is a super-2 number, since 2×1132410412272 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113241041195 and 113241041204.
It is not a weakly prime, because it can be changed into another prime (113241141227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620520613 + 56620520614.
It is an arithmetic number, because the mean of its divisors is an integer number (56620520614).
Almost surely, 2113241041227 is an apocalyptic number.
113241041227 is a deficient number, since it is larger than the sum of its proper divisors (1).
113241041227 is an equidigital number, since it uses as much as digits as its factorization.
113241041227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 113241041227 its reverse (722140142311), we get a palindrome (835381183538).
The spelling of 113241041227 in words is "one hundred thirteen billion, two hundred forty-one million, forty-one thousand, two hundred twenty-seven".
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