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113241230561131 is a prime number
BaseRepresentation
bin11001101111111000000111…
…010100100100111101101011
3112211221202102001200021002021
4121233320013110210331223
5104320321020010424011
61040502145251245311
732565260154643351
oct3157700724447553
9484852361607067
10113241230561131
113309a377505982
121084aaaaba9837
134b257aa10775a
141dd6c94acd7d1
15d159e6e38471
hex66fe07524f6b

113241230561131 has 2 divisors, whose sum is σ = 113241230561132. Its totient is φ = 113241230561130.

The previous prime is 113241230561119. The next prime is 113241230561141. The reversal of 113241230561131 is 131165032142311.

It is a strong prime.

It is an emirp because it is prime and its reverse (131165032142311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113241230561131 - 27 = 113241230561003 is a prime.

It is a super-2 number, since 2×1132412305611312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113241230561111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620615280565 + 56620615280566.

It is an arithmetic number, because the mean of its divisors is an integer number (56620615280566).

Almost surely, 2113241230561131 is an apocalyptic number.

113241230561131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113241230561131 is an equidigital number, since it uses as much as digits as its factorization.

113241230561131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 113241230561131 in words is "one hundred thirteen trillion, two hundred forty-one billion, two hundred thirty million, five hundred sixty-one thousand, one hundred thirty-one".