Base | Representation |
---|---|
bin | 10101000101111101… |
… | …00101111111100011 |
3 | 1002020012120121112121 |
4 | 22202332211333203 |
5 | 141143002032011 |
6 | 5111410005111 |
7 | 550424361223 |
oct | 124276457743 |
9 | 32205517477 |
10 | 11324252131 |
11 | 4891277265 |
12 | 2240576797 |
13 | 10b616710a |
14 | 795d98083 |
15 | 46428de71 |
hex | 2a2fa5fe3 |
11324252131 has 8 divisors (see below), whose sum is σ = 11397302784. Its totient is φ = 11251264200.
The previous prime is 11324252123. The next prime is 11324252141. The reversal of 11324252131 is 13125242311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11324252131 - 23 = 11324252123 is a prime.
It is a super-2 number, since 2×113242521312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11324252096 and 11324252105.
It is not an unprimeable number, because it can be changed into a prime (11324252141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 378196 + ... + 407038.
It is an arithmetic number, because the mean of its divisors is an integer number (1424662848).
Almost surely, 211324252131 is an apocalyptic number.
11324252131 is a deficient number, since it is larger than the sum of its proper divisors (73050653).
11324252131 is a wasteful number, since it uses less digits than its factorization.
11324252131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31361.
The product of its digits is 1440, while the sum is 25.
Adding to 11324252131 its reverse (13125242311), we get a palindrome (24449494442).
The spelling of 11324252131 in words is "eleven billion, three hundred twenty-four million, two hundred fifty-two thousand, one hundred thirty-one".
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