113244000217 has 2 divisors, whose sum is σ = 113244000218. Its totient is φ = 113244000216.

The previous prime is 113244000193. The next prime is 113244000229. The reversal of 113244000217 is 712000442311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113172360921 + 71639296 = 336411^2 + 8464^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113244000217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113244000191 and 113244000200.

It is not a weakly prime, because it can be changed into another prime (113244000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56622000108 + 56622000109.

It is an arithmetic number, because the mean of its divisors is an integer number (56622000109).

Almost surely, 2^113244000217 is an apocalyptic number.

It is an amenable number.

113244000217 is a deficient number, since it is larger than the sum of its proper divisors (1).

113244000217 is an equidigital number, since it uses as much as digits as its factorization.

113244000217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 113244000217 its reverse (712000442311), we get a palindrome (825244442528).

The spelling of 113244000217 in words is "one hundred thirteen billion, two hundred forty-four million, two hundred seventeen", and thus it is an aban number.