Base | Representation |
---|---|
bin | 10101000101111110… |
… | …01010011101111011 |
3 | 1002020012212012110221 |
4 | 22202333022131323 |
5 | 141143021322111 |
6 | 5111413120511 |
7 | 550425552622 |
oct | 124277123573 |
9 | 32205765427 |
10 | 11324401531 |
11 | 4891369533 |
12 | 2240629137 |
13 | 10b61ba111 |
14 | 795dd66b9 |
15 | 4642bd371 |
hex | 2a2fca77b |
11324401531 has 8 divisors (see below), whose sum is σ = 11520057600. Its totient is φ = 11128869480.
The previous prime is 11324401513. The next prime is 11324401537. The reversal of 11324401531 is 13510442311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11324401531 - 29 = 11324401019 is a prime.
It is a super-2 number, since 2×113244015312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11324401496 and 11324401505.
It is not an unprimeable number, because it can be changed into a prime (11324401537) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163650 + ... + 222328.
It is an arithmetic number, because the mean of its divisors is an integer number (1440007200).
Almost surely, 211324401531 is an apocalyptic number.
11324401531 is a deficient number, since it is larger than the sum of its proper divisors (195656069).
11324401531 is an equidigital number, since it uses as much as digits as its factorization.
11324401531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62009.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11324401531 its reverse (13510442311), we get a palindrome (24834843842).
The spelling of 11324401531 in words is "eleven billion, three hundred twenty-four million, four hundred one thousand, five hundred thirty-one".
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