Base | Representation |
---|---|
bin | 110100101111000001… |
… | …0000111000001100001 |
3 | 101211022100202112020121 |
4 | 1221132002013001201 |
5 | 3323412132323212 |
6 | 124005211040241 |
7 | 11116234405063 |
oct | 1513602070141 |
9 | 354270675217 |
10 | 113246761057 |
11 | 44033931811 |
12 | 19b46140081 |
13 | a8aa05b7b1 |
14 | 56a44a1733 |
15 | 2e2c180d07 |
hex | 1a5e087061 |
113246761057 has 2 divisors, whose sum is σ = 113246761058. Its totient is φ = 113246761056.
The previous prime is 113246761049. The next prime is 113246761079. The reversal of 113246761057 is 750167642311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74090662416 + 39156098641 = 272196^2 + 197879^2 .
It is a cyclic number.
It is not a de Polignac number, because 113246761057 - 23 = 113246761049 is a prime.
It is not a weakly prime, because it can be changed into another prime (113246761087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56623380528 + 56623380529.
It is an arithmetic number, because the mean of its divisors is an integer number (56623380529).
Almost surely, 2113246761057 is an apocalyptic number.
It is an amenable number.
113246761057 is a deficient number, since it is larger than the sum of its proper divisors (1).
113246761057 is an equidigital number, since it uses as much as digits as its factorization.
113246761057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 113246761057 in words is "one hundred thirteen billion, two hundred forty-six million, seven hundred sixty-one thousand, fifty-seven".
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