Base | Representation |
---|---|
bin | 11001110000000001100111… |
… | …011001111011101011001001 |
3 | 112211222201202001110001222220 |
4 | 121300001213121323223021 |
5 | 104321002413210342301 |
6 | 1040510553450404253 |
7 | 32566101034050054 |
oct | 3160014731735311 |
9 | 484881661401886 |
10 | 113251432512201 |
11 | 330a37322157a5 |
12 | 10850a77730689 |
13 | 4b267448b32a9 |
14 | 1dd75819c1a9b |
15 | d15de28d8936 |
hex | 67006767bac9 |
113251432512201 has 8 divisors (see below), whose sum is σ = 151002109649664. Its totient is φ = 75500855191440.
The previous prime is 113251432512181. The next prime is 113251432512203. The reversal of 113251432512201 is 102215234152311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113251432512201 - 29 = 113251432511689 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113251432512203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22265401 + ... + 26874726.
It is an arithmetic number, because the mean of its divisors is an integer number (18875263706208).
Almost surely, 2113251432512201 is an apocalyptic number.
It is an amenable number.
113251432512201 is a deficient number, since it is larger than the sum of its proper divisors (37750677137463).
113251432512201 is an equidigital number, since it uses as much as digits as its factorization.
113251432512201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49908351.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 113251432512201 its reverse (102215234152311), we get a palindrome (215466666664512).
The spelling of 113251432512201 in words is "one hundred thirteen trillion, two hundred fifty-one billion, four hundred thirty-two million, five hundred twelve thousand, two hundred one".
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