Base | Representation |
---|---|
bin | 10000011110101111001… |
… | …000001000001111000011 |
3 | 11000021012212220122222201 |
4 | 100132233020020033003 |
5 | 122023342210330111 |
6 | 2224134153014031 |
7 | 144551523531121 |
oct | 20365710101703 |
9 | 4007185818881 |
10 | 1132514542531 |
11 | 3a7329a31049 |
12 | 1635a49b4317 |
13 | 82a460c1b58 |
14 | 3cb5786a911 |
15 | 1e6d52296c1 |
hex | 107af2083c3 |
1132514542531 has 4 divisors (see below), whose sum is σ = 1132517101864. Its totient is φ = 1132511983200.
The previous prime is 1132514542519. The next prime is 1132514542541. The reversal of 1132514542531 is 1352454152311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1132514542531 - 25 = 1132514542499 is a prime.
It is a super-2 number, since 2×11325145425312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1132514542541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426150 + ... + 1564171.
It is an arithmetic number, because the mean of its divisors is an integer number (283129275466).
Almost surely, 21132514542531 is an apocalyptic number.
1132514542531 is a deficient number, since it is larger than the sum of its proper divisors (2559333).
1132514542531 is an equidigital number, since it uses as much as digits as its factorization.
1132514542531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2559332.
The product of its digits is 72000, while the sum is 37.
Adding to 1132514542531 its reverse (1352454152311), we get a palindrome (2484968694842).
The spelling of 1132514542531 in words is "one trillion, one hundred thirty-two billion, five hundred fourteen million, five hundred forty-two thousand, five hundred thirty-one".
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