Base | Representation |
---|---|
bin | 10101000110000100… |
… | …01110011001101001 |
3 | 1002020021100222100201 |
4 | 22203002032121221 |
5 | 141143223012243 |
6 | 5111442232201 |
7 | 550435434451 |
oct | 124302163151 |
9 | 32207328321 |
10 | 11325204073 |
11 | 4891867497 |
12 | 2240955661 |
13 | 10b640b4b1 |
14 | 796164d61 |
15 | 4643cb04d |
hex | 2a308e669 |
11325204073 has 2 divisors, whose sum is σ = 11325204074. Its totient is φ = 11325204072.
The previous prime is 11325204067. The next prime is 11325204097. The reversal of 11325204073 is 37040252311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7619194944 + 3706009129 = 87288^2 + 60877^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11325204073 is a prime.
It is not a weakly prime, because it can be changed into another prime (11325204973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662602036 + 5662602037.
It is an arithmetic number, because the mean of its divisors is an integer number (5662602037).
Almost surely, 211325204073 is an apocalyptic number.
It is an amenable number.
11325204073 is a deficient number, since it is larger than the sum of its proper divisors (1).
11325204073 is an equidigital number, since it uses as much as digits as its factorization.
11325204073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 28.
Adding to 11325204073 its reverse (37040252311), we get a palindrome (48365456384).
The spelling of 11325204073 in words is "eleven billion, three hundred twenty-five million, two hundred four thousand, seventy-three".
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