113255433 has 12 divisors (see below), whose sum is σ = 164027760. Its totient is φ = 75302136.

The previous prime is 113255423. The next prime is 113255449. The reversal of 113255433 is 334552311.

113255433 is a `hidden beast` number, since 113 + 2 + 5 + 543 + 3 = 666.

It is not a de Polignac number, because 113255433 - 2¹² = 113251337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113255397 and 113255406.

It is not an unprimeable number, because it can be changed into a prime (113255413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13191 + ... + 20012.

It is an arithmetic number, because the mean of its divisors is an integer number (13668980).

Almost surely, 2^113255433 is an apocalyptic number.

It is an amenable number.

113255433 is a deficient number, since it is larger than the sum of its proper divisors (50772327).

113255433 is a wasteful number, since it uses less digits than its factorization.

113255433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33588 (or 33585 counting only the distinct ones).

The product of its digits is 5400, while the sum is 27.

The square root of 113255433 is about 10642.1535884425. The cubic root of 113255433 is about 483.8228197971.

It can be divided in two parts, 1132 and 55433, that added together give a palindrome (56565).

The spelling of 113255433 in words is "one hundred thirteen million, two hundred fifty-five thousand, four hundred thirty-three".