Base | Representation |
---|---|
bin | 110100101111011110… |
… | …1110111010100111001 |
3 | 101211100110020100200111 |
4 | 1221132331313110321 |
5 | 3323430140103101 |
6 | 124010530504321 |
7 | 11116514505526 |
oct | 1513675672471 |
9 | 354313210614 |
10 | 113262425401 |
11 | 44041760654 |
12 | 19b4b4350a1 |
13 | a8b0384638 |
14 | 56a65bc14d |
15 | 2e2d727251 |
hex | 1a5ef77539 |
113262425401 has 4 divisors (see below), whose sum is σ = 113263892992. Its totient is φ = 113260957812.
The previous prime is 113262425389. The next prime is 113262425411. The reversal of 113262425401 is 104524262311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113262425401 - 233 = 104672490809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113262425411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611205 + ... + 774658.
It is an arithmetic number, because the mean of its divisors is an integer number (28315973248).
Almost surely, 2113262425401 is an apocalyptic number.
It is an amenable number.
113262425401 is a deficient number, since it is larger than the sum of its proper divisors (1467591).
113262425401 is an equidigital number, since it uses as much as digits as its factorization.
113262425401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1467590.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 113262425401 its reverse (104524262311), we get a palindrome (217786687712).
The spelling of 113262425401 in words is "one hundred thirteen billion, two hundred sixty-two million, four hundred twenty-five thousand, four hundred one".
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