Base | Representation |
---|---|
bin | 110100101111011111… |
… | …0101010010000010011 |
3 | 101211100110121221211111 |
4 | 1221132332222100103 |
5 | 3323430213242003 |
6 | 124010535154151 |
7 | 11116516334641 |
oct | 1513676522023 |
9 | 354313557744 |
10 | 113262634003 |
11 | 44041893352 |
12 | 19b4b515957 |
13 | a8b042857c |
14 | 56a6634191 |
15 | 2e2d768e6d |
hex | 1a5efaa413 |
113262634003 has 2 divisors, whose sum is σ = 113262634004. Its totient is φ = 113262634002.
The previous prime is 113262633971. The next prime is 113262634013. The reversal of 113262634003 is 300436262311.
It is a strong prime.
It is an emirp because it is prime and its reverse (300436262311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113262634003 - 25 = 113262633971 is a prime.
It is a super-2 number, since 2×1132626340032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113262634013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56631317001 + 56631317002.
It is an arithmetic number, because the mean of its divisors is an integer number (56631317002).
Almost surely, 2113262634003 is an apocalyptic number.
113262634003 is a deficient number, since it is larger than the sum of its proper divisors (1).
113262634003 is an equidigital number, since it uses as much as digits as its factorization.
113262634003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 113262634003 its reverse (300436262311), we get a palindrome (413698896314).
The spelling of 113262634003 in words is "one hundred thirteen billion, two hundred sixty-two million, six hundred thirty-four thousand, three".
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