1132644016131 has 8 divisors (see below), whose sum is σ = 1510214299920. Its totient is φ = 755084871552.

The previous prime is 1132644016129. The next prime is 1132644016139. The reversal of 1132644016131 is 1316104462311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1132644016131 - 2¹ = 1132644016129 is a prime.

It is a super-2 number, since 2×1132644016131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1132644016092 and 1132644016101.

It is not an unprimeable number, because it can be changed into a prime (1132644016139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2544586 + ... + 2956383.

It is an arithmetic number, because the mean of its divisors is an integer number (188776787490).

Almost surely, 2^{1132644016131} is an apocalyptic number.

1132644016131 is a deficient number, since it is larger than the sum of its proper divisors (377570283789).

1132644016131 is an equidigital number, since it uses as much as digits as its factorization.

1132644016131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5569605.

The product of its (nonzero) digits is 10368, while the sum is 33.

Adding to 1132644016131 its reverse (1316104462311), we get a palindrome (2448748478442).

The spelling of 1132644016131 in words is "one trillion, one hundred thirty-two billion, six hundred forty-four million, sixteen thousand, one hundred thirty-one".