Base | Representation |
---|---|
bin | 1010010011011111100010… |
… | …1000000101111101111011 |
3 | 1111010010201011220120221022 |
4 | 2210313320220011331323 |
5 | 2441112320001104243 |
6 | 40032532525133055 |
7 | 2246364651105116 |
oct | 244677050057573 |
9 | 44103634816838 |
10 | 11330000019323 |
11 | 3679031702807 |
12 | 132b9b60ba18b |
13 | 64255062378b |
14 | 2b2536b2957d |
15 | 149abc997b68 |
hex | a4df8a05f7b |
11330000019323 has 2 divisors, whose sum is σ = 11330000019324. Its totient is φ = 11330000019322.
The previous prime is 11330000019319. The next prime is 11330000019413. The reversal of 11330000019323 is 32391000003311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11330000019323 - 22 = 11330000019319 is a prime.
It is a super-3 number, since 3×113300000193233 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11330000019292 and 11330000019301.
It is not a weakly prime, because it can be changed into another prime (11330000819323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665000009661 + 5665000009662.
It is an arithmetic number, because the mean of its divisors is an integer number (5665000009662).
Almost surely, 211330000019323 is an apocalyptic number.
11330000019323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330000019323 is an equidigital number, since it uses as much as digits as its factorization.
11330000019323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 26.
The spelling of 11330000019323 in words is "eleven trillion, three hundred thirty billion, nineteen thousand, three hundred twenty-three".
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