11330003321233 has 4 divisors (see below), whose sum is σ = 11593491770608. Its totient is φ = 11066514871860.

The previous prime is 11330003321191. The next prime is 11330003321333. The reversal of 11330003321233 is 33212330003311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11330003321233 - 2⁴¹ = 9130980065681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11330003321198 and 11330003321207.

It is not an unprimeable number, because it can be changed into a prime (11330003321333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131744224623 + ... + 131744224708.

It is an arithmetic number, because the mean of its divisors is an integer number (2898372942652).

Almost surely, 2^{11330003321233} is an apocalyptic number.

It is an amenable number.

11330003321233 is a deficient number, since it is larger than the sum of its proper divisors (263488449375).

11330003321233 is an equidigital number, since it uses as much as digits as its factorization.

11330003321233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 263488449374.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 11330003321233 its reverse (33212330003311), we get a palindrome (44542333324544).

The spelling of 11330003321233 in words is "eleven trillion, three hundred thirty billion, three million, three hundred twenty-one thousand, two hundred thirty-three".