113300220043 has 2 divisors, whose sum is σ = 113300220044. Its totient is φ = 113300220042.

The previous prime is 113300220023. The next prime is 113300220157. The reversal of 113300220043 is 340022003311.

It is a weak prime.

It is an emirp because it is prime and its reverse (340022003311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113300220043 is a prime.

It is a super-3 number, since 3×113300220043³ (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113300220043.

It is not a weakly prime, because it can be changed into another prime (113300220023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56650110021 + 56650110022.

It is an arithmetic number, because the mean of its divisors is an integer number (56650110022).

Almost surely, 2^113300220043 is an apocalyptic number.

113300220043 is a deficient number, since it is larger than the sum of its proper divisors (1).

113300220043 is an equidigital number, since it uses as much as digits as its factorization.

113300220043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 113300220043 its reverse (340022003311), we get a palindrome (453322223354).

The spelling of 113300220043 in words is "one hundred thirteen billion, three hundred million, two hundred twenty thousand, forty-three".