Base | Representation |
---|---|
bin | 1010010011011111101001… |
… | …1011100110110010100011 |
3 | 1111010010210021220000122211 |
4 | 2210313322123212302203 |
5 | 2441112400224102243 |
6 | 40032535530142551 |
7 | 2246365466353660 |
oct | 244677233466243 |
9 | 44103707800584 |
10 | 11330030300323 |
11 | 3679047805329 |
12 | 132ba04281a57 |
13 | 642556996627 |
14 | 2b253ab6ca67 |
15 | 149ac0479d9d |
hex | a4dfa6e6ca3 |
11330030300323 has 4 divisors (see below), whose sum is σ = 12948606057520. Its totient is φ = 9711454543128.
The previous prime is 11330030300191. The next prime is 11330030300539. The reversal of 11330030300323 is 32300303003311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11330030300323 - 225 = 11329996745891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11330030300294 and 11330030300303.
It is not an unprimeable number, because it can be changed into a prime (11330030340323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809287878588 + ... + 809287878601.
It is an arithmetic number, because the mean of its divisors is an integer number (3237151514380).
Almost surely, 211330030300323 is an apocalyptic number.
11330030300323 is a deficient number, since it is larger than the sum of its proper divisors (1618575757197).
11330030300323 is an equidigital number, since it uses as much as digits as its factorization.
11330030300323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1618575757196.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 11330030300323 its reverse (32300303003311), we get a palindrome (43630333303634).
The spelling of 11330030300323 in words is "eleven trillion, three hundred thirty billion, thirty million, three hundred thousand, three hundred twenty-three".
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