Base | Representation |
---|---|
bin | 1010010011011111101101… |
… | …1101011110110110011011 |
3 | 1111010010211111101101020211 |
4 | 2210313323131132312123 |
5 | 2441112414134204212 |
6 | 40032541344231551 |
7 | 2246366066216605 |
oct | 244677335366633 |
9 | 44103744341224 |
10 | 11330047569307 |
11 | 367905652a815 |
12 | 132ba0a00b5b7 |
13 | 64255a43196c |
14 | 2b253d186175 |
15 | 149ac1c3b9a7 |
hex | a4dfb75ed9b |
11330047569307 has 2 divisors, whose sum is σ = 11330047569308. Its totient is φ = 11330047569306.
The previous prime is 11330047569289. The next prime is 11330047569319. The reversal of 11330047569307 is 70396574003311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11330047569307 is a prime.
It is not a weakly prime, because it can be changed into another prime (11330047569397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665023784653 + 5665023784654.
It is an arithmetic number, because the mean of its divisors is an integer number (5665023784654).
Almost surely, 211330047569307 is an apocalyptic number.
11330047569307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330047569307 is an equidigital number, since it uses as much as digits as its factorization.
11330047569307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1428840, while the sum is 49.
The spelling of 11330047569307 in words is "eleven trillion, three hundred thirty billion, forty-seven million, five hundred sixty-nine thousand, three hundred seven".
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