Base | Representation |
---|---|
bin | 1010010011011111101111… |
… | …1111110100100110100011 |
3 | 1111010010212010022201122221 |
4 | 2210313323333310212203 |
5 | 2441112423440240144 |
6 | 40032542305211511 |
7 | 2246366235561514 |
oct | 244677377644643 |
9 | 44103763281587 |
10 | 11330056571299 |
11 | 3679060619084 |
12 | 132ba11030b97 |
13 | 64255c26419b |
14 | 2b254044aa0b |
15 | 149ac2918d84 |
hex | a4dfbff49a3 |
11330056571299 has 2 divisors, whose sum is σ = 11330056571300. Its totient is φ = 11330056571298.
The previous prime is 11330056571293. The next prime is 11330056571413. The reversal of 11330056571299 is 99217565003311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11330056571299 is a prime.
It is not a weakly prime, because it can be changed into another prime (11330056571293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665028285649 + 5665028285650.
It is an arithmetic number, because the mean of its divisors is an integer number (5665028285650).
Almost surely, 211330056571299 is an apocalyptic number.
11330056571299 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330056571299 is an equidigital number, since it uses as much as digits as its factorization.
11330056571299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1530900, while the sum is 52.
The spelling of 11330056571299 in words is "eleven trillion, three hundred thirty billion, fifty-six million, five hundred seventy-one thousand, two hundred ninety-nine".
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