1133023313131 has 4 divisors (see below), whose sum is σ = 1133387749600. Its totient is φ = 1132658876664.

The previous prime is 1133023313099. The next prime is 1133023313207. The reversal of 1133023313131 is 1313133203311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133023313131 - 2⁵ = 1133023313099 is a prime.

It is a super-2 number, since 2×1133023313131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133023313096 and 1133023313105.

It is not an unprimeable number, because it can be changed into a prime (1133023013131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182213571 + ... + 182219788.

It is an arithmetic number, because the mean of its divisors is an integer number (283346937400).

Almost surely, 2^{1133023313131} is an apocalyptic number.

1133023313131 is a deficient number, since it is larger than the sum of its proper divisors (364436469).

1133023313131 is an equidigital number, since it uses as much as digits as its factorization.

1133023313131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364436468.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1133023313131 its reverse (1313133203311), we get a palindrome (2446156516442).

The spelling of 1133023313131 in words is "one trillion, one hundred thirty-three billion, twenty-three million, three hundred thirteen thousand, one hundred thirty-one".