113305255254953 has 2 divisors, whose sum is σ = 113305255254954. Its totient is φ = 113305255254952.

The previous prime is 113305255254943. The next prime is 113305255255043. The reversal of 113305255254953 is 359452552503311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110241663157609 + 3063592097344 = 10499603^2 + 1750312^2 .

It is a cyclic number.

It is not a de Polignac number, because 113305255254953 - 2⁴ = 113305255254937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113305255254895 and 113305255254904.

It is not a weakly prime, because it can be changed into another prime (113305255254943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56652627627476 + 56652627627477.

It is an arithmetic number, because the mean of its divisors is an integer number (56652627627477).

Almost surely, 2^{113305255254953} is an apocalyptic number.

It is an amenable number.

113305255254953 is a deficient number, since it is larger than the sum of its proper divisors (1).

113305255254953 is an equidigital number, since it uses as much as digits as its factorization.

113305255254953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12150000, while the sum is 53.

The spelling of 113305255254953 in words is "one hundred thirteen trillion, three hundred five billion, two hundred fifty-five million, two hundred fifty-four thousand, nine hundred fifty-three".