Base | Representation |
---|---|
bin | 1010010011100011010011… |
… | …1100111111110111101011 |
3 | 1111010020022201101020222021 |
4 | 2210320310330333313223 |
5 | 2441121403101213311 |
6 | 40033221202205311 |
7 | 2246432020655653 |
oct | 244706474776753 |
9 | 44106281336867 |
10 | 11331012132331 |
11 | 3679500a4a241 |
12 | 1330039053837 |
13 | 642682212208 |
14 | 2b25d130b363 |
15 | 149b2b76d171 |
hex | a4e34f3fdeb |
11331012132331 has 2 divisors, whose sum is σ = 11331012132332. Its totient is φ = 11331012132330.
The previous prime is 11331012132211. The next prime is 11331012132353. The reversal of 11331012132331 is 13323121013311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331012132331 - 211 = 11331012130283 is a prime.
It is a super-2 number, since 2×113310121323312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331012132296 and 11331012132305.
It is not a weakly prime, because it can be changed into another prime (11331012102331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665506066165 + 5665506066166.
It is an arithmetic number, because the mean of its divisors is an integer number (5665506066166).
Almost surely, 211331012132331 is an apocalyptic number.
11331012132331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331012132331 is an equidigital number, since it uses as much as digits as its factorization.
11331012132331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11331012132331 its reverse (13323121013311), we get a palindrome (24654133145642).
The spelling of 11331012132331 in words is "eleven trillion, three hundred thirty-one billion, twelve million, one hundred thirty-two thousand, three hundred thirty-one".
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